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What is relative density?

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Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. Specific gravity usually means relative density with respect to water.
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Native English Speaker with 32 years experience in teaching English and communication skills.

Relative density is the ratio of the density of a substance to the density of water.
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Mathematics

it is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. it is also known as specific gravity. Specific gravity usually means relative density with respect to water.
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The ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas
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it is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. it is also known as specific gravity. Specific gravity usually means relative density with respect to water.
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In general way density of a material w.r.to a reference material is called relative density of the material w.r.to the reference material. And in case of reference water taken as water, the relative density is known as specific gravity
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Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. Specific gravity usually means relative density with respect to water. The term "relative density" is often preferred in modern scientific usage.
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Relative density the ratio of the density of a substance to the density of a reference substance.
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Related Questions

Two long parallel conductors carry 100 A. If the conductors are separated by 20 mm, the force per meter of length of each conductor will be a.) 100 N. b.) 10 N. c.) 1 N. d.) 0.01 N.
Given data: Current I1 and I2 = 100 Amps; Distance = 20 mm = 20 × 10-3 m; Force = ? We know that the force is found by the following expression. Torque developed force fT=M0 *I1 *I2/(2*(Pi)*d)=4*(Pi)*(10)^-7 *(100)^2/2*(pi)*20*(10)^-3=0.1 N
Kumar Upendra Akshay
I was enrolled to a coaching for 11th and 12th standard. Due to my low performance in JEE advanced I want to give 1 more year to prep. I have all the study material. I am planning to just solve that and join test series. But the problem is how to get my doubts cleared? And will this strategy work?
you can look out for online tutors who can clear your doubts. Also there are many online forums available that can help you with the same. Look out for tricks that are available on Youtube. you can also opt for online test series.
Priyanshu

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