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There are six men and four women on the city council. If the council number is selected for a committee at random. How is likely it that it is a woman ?

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Jee Tutor

0.4
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Data Analytics & Advanced Statistics Tutor with 18 years of experience in teaching

Probability (Woman)=4C1/10C1
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Tutor

2/5
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GMAT Math Expert

Total Number of people = 6 Men + 4 Women. Now 1 women can be selected out of 4 Women in 4C1 ways= 4 ways. Total number of ways in which a member is selected is 10C1 ways = 10 ways. Probability for a women to get selected is 4/10 = 0.4.
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Trainer

P(w) = 4C1/10C1= 4/10 = 2/5= 0.4
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4
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Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

There are 10 members of the council. Any one may be selected for a committee. No. of possible cases = 10 . One woman out of 4 may be selected in 4 ways. No. of favourable cases = 4 Probability of selection of a woman = 4/10 = 0.4
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The council number is selected for a committee at random from 10members (6 men + 4 women) is n (S) = 10c1 = 10 since the council number is a women then the required event n(E) = 4c1 = 4 the required probability is p(E) = n(E) / n(S) = 4/10 = 2/5
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Mathematics Expert

Use the concept of selection i.e ncr!!!!
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ECONOMICS-MATHEMATICS-STATISTICS

4/10=.4 thus 40% chance
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