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The magnitude of a magnetic force ‘F’ acting on charge ‘q’ when it moves with a velocity ‘v’ through a magnetic field ‘B’ is given by __________. (F = qvBsinq, F = qv2Bsinq, vBsinq, None of these)

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F = qvBsin(theta)
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Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

The magnitude of a magnetic force ‘F’ acting on charge ‘q’ when it moves with a velocity ‘v’ through a magnetic field ‘B’ is given by F = qvBsinq
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Tutor

F = qvBsin(theta)
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Physics Tutor

qvBsin(theta) where theta is angle between v and B.
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Tutor

qvBsin(theta)
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qvbsin(anle between b& v)
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Entrance coaching for JEE/CET (Physics, Chemistry n Maths)

Please rephrase the question as one should not use the same variable for two different physical quantities.
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Quicker Maths

None of these,because here q is the charge not the angle the angle between vector (v) and vector (B). hence the our answer is F = qv * B (i.e cross product of qv and B vector)
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Chemistry Specialist

F=qvbsinq
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Tutor

Sorry but u didnt mention the angle between the charge and magnetic field and q is charge here we can't use it with sin. so None of these. If u have given the angle between the velocity and magnetic field then the force will be equal to qvBsin(angle between them).
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