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The magnetic force Fm acting on charge ‘q’ when it moves with a velocity ‘v’ through a magnetic field ‘B’ is given by __________. (Fm = qv x B, Fm = qv2 x B, Fm = qE, None of these)

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Fm = qv x B
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Fm = qv x B
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Fm=qv x B
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A. Fm= qv x B
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Fm= qvBsinX. It is Maximum when X= 90 degree. Therefore the question must be rephrased as considering the particle to be perpendicular to the magnetic field. In that case Fm= qvB
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qv*B
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