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The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity v perpendicular to the circle, what is the mass of the air passing through it in time t? (b) What is the kinetic energy of the air? (c) Assume that the windmill converts 25% of the wind’s energy into electrical energy, and that A = 30 m2, v = 36 km/h and the density of air is 1.2 kg m-3 . What is the electrical power produced?
Asked by Abhay Last Modified
Answer 
Mohit Saxena
Ex Iitian With Experience of 17 Years, mentor of Jee rank 13,15,66,71
m*(kg/sec)= (density of air )x Axv where v=36 km/h = 10m/s
m*= 360kg/sec let unit of time 't' is in Second
mass = 360t kg
kinetic energy = .5x (density of air)x(swept area of windmill)x(velocity of air)³
K.E.= 18000 jule/sec
power produced = .25x 18000= 4500 jule/sec
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