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If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?

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Maths and Physics teaching For XI, XII, IIT Jee Level , Quant and DI for CAT/GMATE/GRE aspirents

2/7
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2/7
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Tutor

366/7 gives 2 remainder. two possible cases out of 7 thus prob of 53 Tuesdays = 2/7
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M.Sc.,B.Ed.,M.C.A.

2/7
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Tutor/Trainer

A leap year has 366 days. 366/7 gives 52 weeks + 2 days. So in a week there are 7 days. The probability of getting one tuesdayin a week must be 1.monday and tuesday 2.tuesday and wednesday. So the answer is 2/7
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2/7
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Spoken English, BTech Tuition, C Language, C++ Language, CAD etc., with 4 years of experience

Sorry that was for a different question. Its 2/7 ofc.
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Data Analytics & Advanced Statistics Tutor with 18 years of experience in teaching

Prob of 53 tuesdays=2/7
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AARAV Mathematics Classes

2/7
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Native English Speaker with 32 years experience in teaching English and communication skills.

366/7 = 52 with a remainder 2. Therefore 2/7 possible way
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