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I want to crack NEET. What should I do now? I am in 11th standard.

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Learn Class XI-XII Tuition (PUC) +1 Physical Education

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Physics Teacher

Basically complete your boards syllabus as early as possible and then start studying study material from a good institute. Practice by giving test .
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Tutor

Work hard under the guidance of a knowlegeable teacher who is well versed in his subjects. Put special stress on Physics and Physical chemistry as they contain numerical problems which act like an obstacle for non math students. Mostly, it is observed that students preparing for NEET lag behind in Physics...
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Work hard under the guidance of a knowlegeable teacher who is well versed in his subjects. Put special stress on Physics and Physical chemistry as they contain numerical problems which act like an obstacle for non math students. Mostly, it is observed that students preparing for NEET lag behind in Physics and Physical Chemistry. In short, work on your week links. read less
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B. Tech. (elec) [IIT/Kanpur - 1978] teaches Physics beyond the textbook.

NEET has syllabus of Class XI and XII. Study class XI subjects with NEET (to clear) as target (and not XI). Similarly when you go to class XII, do it the same way. Start preparing for NEET from to-day.
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NCERT books r best to crack the exam
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Home Tutor

Answer...u should do some previous years question papers and focused on ncert books.......and practice with good effort
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Regular Practice & take the admission in good coaching institute for proper guidence
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Tutor

Start preparing. Side by side...
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Tutor

gather information about NEET exam (syllabus+materials+coaching) + understand & analyse concepts + Hard work with smart techniques + patience & planning = crack exam intelligently to overcome heavy competition.
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Physics Tutor

Get up and get started :) Go for NCERT in Biology and Chemistry and follow your school prescribed Physics reference book.Practice with DC Pandey objective book too
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The amount of heat required to raise the temperature of 2.0 x 108kg of water from 0°C to 100°C is equal to __________. (9 x 1013J, 9 x 1012J, 9 x 1011J, 9 x 1010J)
Q=mc?T, where Q= amount oh heat required to raise the temperature by ?T c- specific heat capacity of the substance ?T- Temperature difference m-mass of the substance So,...
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Evaluate: 8! - 3!?
8!=8*7*6*5*4*3*2*1 3!=3*2*1 8!-3!=8*7*6*5*4*3*2*1-3*2*1 =3*2*1(8*7*6*5*4-1) =6(6720-1) =6(6719) = 40314 Ok all the best.
Deepa
Describe a situation when someone gave positive comments about the work you did for them.
Positive comments always motivates to improve our performance by enhancing ability,encouraging effort and acknowledging results. It somehow make us to improve our efficiency and reduce our mistakes.we get positive vibes and try to work hard.
Chandandeep
A point pole has a strength of 4? × 10-4 weber. The force in newtons on a point pole of 4? × 1.5 × 10-4 weber placed at a distance of 10 cm from it will be a.) 20 N. b.) 15 N. c.) 7.5 N. d.) 3.75 N.
Solution: m1 = 4N × 10^-7, m2 = 4N × 1.5 × 10^-4; r = 10 cm. F= (m1 m2)/( 4 pi mue0 r^2) = (4N 10^-7 x 4N 10^^-4)/(4N x 4N x 10^-7(10 x10^-2)^2 =15N
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