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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > Force on a charged particle moving in a magnetic field...
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Force on a charged particle moving in a magnetic field is given by the equation F = qvbsinq. Quantities mutually perpendicular are __________. (V and B, F and v, F and B, None)

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Khan's Physics

Force is given by cross product F = q(v x B), hence F and v, and F and B are two perpendicular pairs.
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Don't want to over express myself, just join and feel the experience.

F and v
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The above equation is a simplified version of F = q (v X B). Where v and B are vectors and q is a scalar. As you know any vector has magnitude and direction whereas scalars have only magnitude. Whenever there is a cross product between two vectors then the direction of resultant vector is perpendicular...
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The above equation is a simplified version of F = q (v X B). Where v and B are vectors and q is a scalar. As you know any vector has magnitude and direction whereas scalars have only magnitude. Whenever there is a cross product between two vectors then the direction of resultant vector is perpendicular to the plane formed by two vectors whose cross product is carried out. So, F as a vector would be perpendicular to both v and B vector. But the equation given is for the magnitude of F not the direction. So, strictly speaking the answer would be none of these. Now, if the question has multiple answers then you will go with F and v and F and B. Whereas if it has single answer then go with none of these. read less
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Also q being a scalar has no effect on the direction of F
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v and B
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Headstart to assured 95+ score in math

c
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v&b
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