UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 12 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > Find the probability that a non leap year has 53 sunday...
✕

Search in

Find the probability that a non leap year has 53 sundays..

Asked by Last Modified  

18 Answers

Learn Class XI-XII Tuition (PUC)

Follow 3
Answer

Please enter your answer

SME in Mathematics & Statistics

A non leap year has 365 days. There are 52 weeks each having 7 days. This amounts to 52 x 7 = 364 days. The remaining 1 day can be any day among Monday, Tuesday,..., Sunday. Hence the required probability is 1/7.
Comments
Dislike Bookmark

Tutor

As there are 52 weeks in a year. 52 weeks correspond to 7*52=364 days. So, the last day is the one which should be a Sunday for you to get 53 Sundays. Sample space has seven days as options. So probability of getting 53 Sundays in a non-leap year is 1/7
Comments
Dislike Bookmark

Tutor

1/7
Comments
Dislike Bookmark

Spoken English, BTech Tuition, C Language, C++ Language, CAD etc., with 4 years of experience

52 weeks*7 days per week = 364 days The remaining day in case of a non leap year is 1 (365-364) The possibilities of this day are Sun, Mon, Tue, Wed, Thu, Fri, Sat = 7 The favorable outcome = Sun = 1 Therefore the probability of getting 53 sundays in a non leap year = 1/7
Comments
Dislike Bookmark

Coaching

Probability of getting 53 Sundays in a non leap year = 1/7
Comments
Dislike Bookmark

Tutor

1/7
Comments
Dislike Bookmark

Pursuing my IAS goal since 2010-11

Divide 365 by 7, we get 1 remainder. 365 days has 52 weeks and a extra day which can be any day among mon,tue,wed....sun. So 53rd sunday probability=1/7.
Comments
Dislike Bookmark

Headstart to assured 95+ score in math

1/7 i think.
Comments
Dislike Bookmark

Native English Speaker with 32 years experience in teaching English and communication skills.

1/7
Comments
Dislike Bookmark

Tutor

the answer is 1/7
Comments
Dislike Bookmark

View 16 more Answers

Related Questions

It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number? A. (216 + 1) B. (216 - 1) C. (7 x 223) D. (296 + 1)
216+1
Srikanth
Two long parallel conductors carry 100 A. If the conductors are separated by 20 mm, the force per meter of length of each conductor will be a.) 100 N. b.) 10 N. c.) 1 N. d.) 0.01 N.
Given data: Current I1 and I2 = 100 Amps; Distance = 20 mm = 20 × 10-3 m; Force = ? We know that the force is found by the following expression. Torque developed force fT=M0 *I1 *I2/(2*(Pi)*d)=4*(Pi)*(10)^-7 *(100)^2/2*(pi)*20*(10)^-3=0.1 N
Kumar Upendra Akshay
The transitions of inner- shell electrons in heavy atoms give rise to _________
xrays
Narendra Kumar
0 0
9
What is focal chord?
If a line be drawn through the focus and parallel to the directrix, it will intersect the parabola at two points that lie a distance 2 p from the focus. The line segment connecting these two points is called the focal chord.
Ganesh
0 0
5
A forward biased p-n semiconductor diode is called __________. (L.E.D, Photodiode, Photovoltaic cell, transistor
LED
Narendra Kumar
1 0
8

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Tension
Tension is a special type of force which is applicable in a stretchable body like rope or string. Its direction is towards the pulley. If rope or chain is massless,frictionless or smooth, then tension...
S

Shivendra Kumar

4 0
0
Parabola
f (x) = a(x - h)2 + k, where (h, k) is thevertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function. Some say f (x) = ax2...

Sameer Ninawe

1 0
0
For IIT/NEET Aspirants Class 12 Chemistry: Positron And Beta Decay.
Beta particle is a high energy, high speed electron or positron emitted in the radioactive decay of an atomic decay of an atomic nucleus, such as a potassium - 40 nucleus. The positron or antielectron...

Nidhi T.

0 0
0
Various Methods of Depreciation
Dear students,Depreciation refers to a phenomenon where the value of a fixed asset falls year on year. This change is due to obsolescence in technology, efflux of time and wear and tear of the fixed asset...

Madhura Sagar G.

2 0
0
Get smarter in physics
Hi all, As we all know Physics is a conceptual subject and if you do the plane reading you will learn nothing.Its subject which can be related with numerics, practicals and relation with the happening...

Ashish Chand

1 0
0

Recommended Articles

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Find PUC Tuition near you
PUC Tuition in Delhi
PUC Tuition in Bangalore
PUC Tuition in Hyderabad
PUC Tuition in Kolkata
PUC Tuition in Mumbai
PUC Tuition in Chennai
PUC Tuition in Pune
PUC Tuition in Jaipur
PUC Tuition in Lucknow
PUC Tuition in Noida
Online Tuition Class 12

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 12 Tuition Classes?

The best tutors for Class 12 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 12 Tuition with the Best Tutors

The best Tutors for Class 12 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved