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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > Evaluate: 8! / 6! * 2!?
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Evaluate: 8! / 6! * 2!?

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8!/(6!*2!) = (8*7*6!)/(6!*2*1) = 8*7/2 = 4*7 = 28
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8!/6!2!=8*7*6!/6!*2*1 =8*7/2 =56/2 =28 answer is 28
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8!/6!=8x7=56. 56x2!=56x2=112.
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Teacher for 8th-12th)

8!=8x7x6x5x4x3x2x1, 6!=6x5x4x3x2x1, 2!=2x1, => 8!/6!*2!=8x7/2=28.
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The problem should be mentioned more clearly. Is it (8!/6!)*2! or 8!/(!6*!2)? If it is (8!/6!)*2! Then the solution: 8! = 8x7x6x5x4x3x2x1, 6! = 6x5x4x3x2x1, 2!=2. So, (8!/6!)*2! = 56x2 = 112. If it is 8!/(6!*2!) The the solution: 8! = 8x7x6x5x4x3x2x1, 6! = 6x5x4x3x2x1, 2!=2. So, 8!/(6!*2!) = 56/2 =...
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The problem is not clear. If we consider the problem as (8!/6!) * 2! we can proceed like this: 8! can be written as 8*7*6!. 6! can be cancelled both in the numerator and denominator. We are left with 8*7*2 ( since 2! = 2*1 =2) = 112. If we consider the problem as 8!/(6!*2!). we get 28.
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