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Asked by Shivani Last Modified
Answer 
Total heat in this process=6000-5500-3000+3500
=1000J
Total work in this process=w1+w2+w3+w4
=2500-1000-1200+x
W=300+x
Total heat=Total work
Q=W
1000=300+x
So. x=700
n=net work done/total heat absorbed
n=1000×100/(6000+3500)=10.5%
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