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A rain drop of radius 2 mm falls from a height of 500 m above the ground. It falls with decreasing acceleration (due to viscous resistance of the air) until at half its original height, it attains its maximum (terminal) speed, and moves with uniform speed thereafter. What is the work done by the gravitational force on the drop in the first and second half of its journey? What is the work done by the resistive force in the entire journey if its speed on reaching the ground is 10 ms-1 ?

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JEE/NEET Physics classes as special tutions

gravitational work =mgh for first half will be 4/3 x3.14 x(.2 x0.2x0.2)x 9.8 x250 = 82 J in each case now work don by resistive force is 82-final KE 82-(.5 x .008 x 10 x10) =81.6J
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