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A polygon has 44 diagonals then how many numbers of sides it has?

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11 sides
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Home Tutor

The answer is 11 sides. You are required to solve the equation 44 diagonals ={n(n-1)/2} - n, where n is the number of sides of the polygon. Hope you have got your answer.
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nC2-n=44 Solving this equation will give you the value of number of sides.
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GMAT Math Expert

n(n-3)/2 = 44 -> n=11. The number of sides of the polygon is 11.
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11
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Graduate

11 sides . no of diagonals = n(n-3)/2
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Counseling Psychologist, Special Educator in LD,.Educational Psychologist, School Counselor.

Given: diagonal of a polygon= 44 To find: no: of sides of a polygon (n) =? No: of diagonal of a polygon = n (n-3)/2 44=n^2-3n/2 88=n^2-3n n^2-3n-88=0 by factorising method we get n^2+8n-11n-88 n(n+8) -11(n+8) (n+8) (n-11) Therefore n= 11
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its easy.. D is the number of diagonals and n is the number of sides D=n(n-3)/2 now substitute the given diagonals let it be 44 as you said or any number you wil get the exact number of sides.
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