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Tan (A+B) = p , Then (A - B) = q , then prove that value of Tan 2A = p+q / 1+pq

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Math Educator for Std.11th ,12th , Engineering Entrance and Degree Level with 11+ Years Experience

Tan2A = tan ((A+B) + (A - B)) = tan (A + B) + tan ( A - B) / 1 - tan (A + B) . tan( A - B) = (p + q) / (1 +pq)
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Tutor

To prove tan2A= (p+q)/ (1-pq) Let A+B = X and A-B = Y. Therefore X+Y=2A Given tanX = p and tanY= q. To find: tan2A = tan(X+Y) = (tanX+tanY)/ (1-tanXtany) = (p+q)/(1-pq) Hence proved.
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Teacher

In this case, Tan(2A) = (p+q)/(1-pq). Denominator is not (1+pq)
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Mathematician

If Tan (A+B) = p , Tan (A - B) = q p+q / 1+pq Tan (A+B) + (A - B) /1+Tan (A+B) *tan (A - B)=Tan(A+B+A-B) = tan2A
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Trainer

This is not a question for class IX-X
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A true teacher of Science and Math

Write Tan{ (A+B) + (A- B) } solve it nd get what u waana these are all R D Sharma question
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M Sc,B Ed

tan((A+B)+(A-B))=Tan(A+B)+Tan(A-B)/1-Tan(A+B)Tan(A-B)=p+q/1-pq,A+B+A-B=2A, ieTan2A=p+q/1-pq
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