UrbanPro

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

Solve : 141x + 103y = 217; 103x + 141y = 27

Asked by Last Modified  

Follow 12
Answer

Please enter your answer

Tutor

First add both equations, we'll get 244x+244y=244, Now, Divide this equation by 244, it gives x+y=1.....(a) Again, subtract equation 2 from 1, it gives 38x-38y=190, Now, divide this equation by 38,comes x-y=5.....(b) Now add equation (a)and(b), implies 2x=6 we get x=3 Now put the value of x in (a),...
read more
First add both equations, we'll get 244x+244y=244, Now, Divide this equation by 244, it gives x+y=1.....(a) Again, subtract equation 2 from 1, it gives 38x-38y=190, Now, divide this equation by 38,comes x-y=5.....(b) Now add equation (a)and(b), implies 2x=6 we get x=3 Now put the value of x in (a),gives y=-2. read less
2 Comments

Tutor

X=3, Y=-2
Comments

B. Com. (Hons.), B. Ed.

Adding both equations we get 244x+244y=244 X+y=1. (3) Subtracting both equations we get 38x-38y=190 X-y=5. (4) Now by adding equations 3 & 4 we get 2x=6 => X=3 Substituting value of x in equation 3 we get 3+y=1 => Y=1-3 =>Y =-2 Sol x= 3 & y= -2
Comments

The Best Tutor You Can Have, Students Come First, UPSC Aspirant

The answer is explained through the image.
Comments

Add both equations you will get x+y=1 Subtract both equatins will get x-y= 5 X=3 Y=2
Comments

Eco, Maths and Stats Tutor

141x+103y=217 ..........(1) 103x+141y=27..............(2) Add (1) and (2). So, (1) + (2) is 244x + 244y=244 -> x + y=1 ................(3) Subtract (2) from (1). So, (1) - (2) gives 38x - 38y=190 -> x - y =5......................(4) Now, the two simplified equations are x + y = 1..........(3) x...
read more
141x+103y=217 ..........(1) 103x+141y=27..............(2) Add (1) and (2). So, (1) + (2) is 244x + 244y=244 -> x + y=1 ................(3) Subtract (2) from (1). So, (1) - (2) gives 38x - 38y=190 -> x - y =5......................(4) Now, the two simplified equations are x + y = 1..........(3) x - y = 5...........(4) Adding (3) and (4), 2x = 6 or x = 3. Again, (3) - (4) gives 2y = -4 or y = -2. read less
Comments

Teacher

x=3 and y = -2
Comments

Teacher

are is 30 cm square
Comments

Progressive classes.

Let consider 141x + 103y = 217.....equation (1) 103x + 141y=27..equation(2) Multiple eq(1) by 103 we get.. 14523x + 10609y=22352..eq(3) Similarly multiple eq(2) by 141 we get.. 14523x + 19881y=3807..eq(4) Now solve eq 3 nd 4 14523x +10609y=22351 14523x+19881y=3807 - ...
read more
Let consider 141x + 103y = 217.....equation (1) 103x + 141y=27..equation(2) Multiple eq(1) by 103 we get.. 14523x + 10609y=22352..eq(3) Similarly multiple eq(2) by 141 we get.. 14523x + 19881y=3807..eq(4) Now solve eq 3 nd 4 14523x +10609y=22351 14523x+19881y=3807 - - - ____________________ -9272y= 18544 Y= -2 Put y=-2 in eq (1) 141x + 103×(-2)=217 141x - 206=217 141x=206+217 141x=423 X=3 So we get X=3 & Y=-2 read less
Comments

Struggle makes you more stronger

1/2*base*height =area 1/2*12*5=30
Comments

View 11 more Answers

Related Questions

How to learn math online?

Via skype you can teach everything online
Robin

How do we find median of given numbers ?

First we need to arrange numbers in increasing order. The value of middle term will be the MEDIAN. In case no. Of terms is odd then the middle term will be (n+1)/2, n being number of terms. But in case...
Sushil Kumar
ABCD is a quadrilateral in which AD = BC and ?DAB = ?CBA. Prove that ?ABD ? ?BAC.
Dear Sarath, let me correct your question, you put ? instead of ∠ So correct question should be: ABCD is a quadrilateral in which AD = BC and ∠DAB = ∠CBA. Prove that ∠ABD = ∠BAC. Solution: In ΔABD...
Sharath
0 0
7

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Composite Numbers
Natural numbers having more than two factors are called Composite numbers. 4, 6, 8, 9, 10, 12, 14, 15, 16, 18… are composite numbers. Number 1 is neither prime nor composite number. All even...

ABC Is An Equilateral Triangle With Side Length 6. If x Is A Point On Side CA, What Is The Minimum Value Of Bxâ² + Xcâ²?
Q. ABC is an equilateral triangle with side length 6. If X is a point on side CA , what is the minimum value of BX² + XC² ? Answer: Let's D is mid point of CA (BD = height =...

MAXIMA AND MINIMA
QUESTION In a college, where every student follows at least one of the three activities- dance, music, or sports- 65% follow dance, 86% follow music, and 57% follow sports. What can be the maximum...

How to Prepare for Maths and get Good Marks, This is In Hindi
Hola Amigos, So In this Video you will get to know the overview on how to prepare for maths and get 100 out of 100. Watch it out! youtubeembedcode.com/nl/http://add-link-exchange.comyoutubeembedcode.com/nl/add-link-Exchangeyoutubeembedcode.com/de/add-link-exchange.comyoutubeembedcode.com/es/add-link-Exchangeyoutubeembedcode...

NUMBER SYSTEM
NUMBER A mathematical symbol represented by a set of digits is called a number.we can express a number in two, i.e., in words & in figures.e.g., if a number is 3290, then we can write this number...
D

Deepa Thakur Sharma

2 0
1

Recommended Articles

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more