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Show that x = 2 and y = 1 satisfy the linear equation 2x 3y = 7.

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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

2x + 3y=7 Put 2 in place of x and 1 in place of y. 2*2+ 3*1=4+3=7
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Yes, it satisfy the equation 2x+3y = 7 putting x=2, y= 1, 2(2) + 3(1) = 4 + 3 = 7
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The equation gets satisfied when we put x=2 and y=1 in 2x + 3y = 7,2(2) + 3(1) = 7.
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Given, 2x+3y=7. Put the value of x and y in the above equation. 2(2) + 3(1) = 7 4+3=7 7=7
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Spoken English trainer and french trainer with 4 years of experience.

the equation gets satisfied if u put X=2 and Y=1 for the given equation 2x+3y=7. so 2(2)+3(1)=7 4+3=7 LHS=RHS HENCE SATISFIED
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Home Tutor

2x + 3y=7. Therefore, put 2 in place of x and 1 in place of y. then the linear equation will be satisfied, 2*2+ 3*1=4+3=7.
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According to question there is no + sign between 2x 3y. If we assume presences of + sign then it satisfy. Otherwise not.
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Math Magician

When the given linear equation is written in the form 2x+3y=7 Then we have to substitute the values in the given equation which satisfies it
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Teacher

On the LHS, if we put the value of x as 2 and y as 1; we will get the equation as 2(2) + 3(1), which after solving comes to 4 + 3, which is equal to RHS i.e. 7. Hence the value of x = 2 and y = 1 satisfy the given equation.
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Maths Expert

Given, 2x+3y=7. Put the value of x and y in the above equation. 2(2) + 3(1) = 7 4+3=7 7=7
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