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Class 10 > Learn Mathematics > One side of a rectangle exceeds its other side by 2...
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One side of a rectangle exceeds its other side by 2 cm. If its area is 195 sq. cm, determine the sides of the rectangle?

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13, 15.
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13 and 15.
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Short method: The difference between side1 and side 2 is Two and area is 195 so we can do multiplication of side 1 and side 2 up to getting area 195 base area of rectangle = side1×side2 (formula). Such as 10×12=120 (not answer) 11 x 13 =141(not answer) 13×15 =195 (answer) Side1 = 13 side2=15.
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Let the breadth be x, then length =x+2 (according to the question). Also, area of rectangle=length * breadth i.e, 195= x(x+2) x2+2x-195 = 0 x2+15x-13x-195 = 0 (x+15)(x-13) = 0 i.e, x=13 [x cannot be negative value, so x! = -15) Hence, breadth is 13 cm while length is 13+2 =15 cm.
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13cm, 15cm
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