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Class 10 > Learn Class IX-X Tuition > How will I calculate the mass of 1 molecule of Nitrogen...
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How will I calculate the mass of 1 molecule of Nitrogen gas?

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Math & science expert.

nitrogen gas is define as N2. its moleculer mass will become 28. for its one mole it is of 28gram. according to mole concept in one mole there is 6.022*10^23 moles are present. so mass of 1 molecule of nitogen gas is 28/(6.022*10^23) gram. solve it and u will get answer.
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Professional Tutor with 15 years of experience.

Actually mass of 1 atom of nitrogen is 14 u(u=atomic mass unit) mass of 1 mole=mass of 1 atom of nitrogen * Avagadro's no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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Trainer

Nitrogen molecular mass is 28 1mole of n2 is 28gram For 1molecule of nitrogen divide 28by avagadro number 6.022×10^23 So ans will be 28/6.022×10^23=4.64×10^-23
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PMT Qualified

Nitrogen always exists as a dimer so the mass of the molecular is to be calculated by multiplying atomic mass of nitrogen by 2 which means 14*2=28
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Physics Teacher

First of all calculate the molar mass of Nitrogen gas & then divide it by Avogadro number
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1 mole of Nitrogen has 28 g mass. As Nitrogen gas is made up of two Nitrogen elements Each nitrogen has Atmoic mass 14 g so N2 will have 2x14 = 28 g.
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As we know that no. of moles = Given mass/molar mass also no. moles = no.of particles(atoms,molecules etc)/avogadro no.(No) as we know Avogadro's number=6.023*10^23 so no. of moles=1/6.023*10^23 molar mass of nitrogen = 14*2=28 so no. of moles = mass/28 1/6.023*10^23=mass/28 mass=28/6.023*10^23...
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Enriching experience of 8 yrs in teaching

14 grams Mass = number of moles x molar mass 1 mole= Relative mass in grams of that particular element
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mass of 1 mole=mass of 1 atom of nitrogen * Avagadro's no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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Excellence Award Winner ( 7 times )

its 14 gm. actually mass of 1 atom of nitrogen is 14 u(u=atomic mass unit) mass of 1 mole=mass of 1 atom of nitrogen * Avagadro's no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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