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Check which of the following are solutions of the equation x – 2y = 4 and which are
not: (i) (0, 2) (ii) (2, 0) (iii) (4, 0) (iv)  (v) (1, 1)

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(i) (0, 2) Putting x = 0 and y = 2 in the L.H.S of the given equation, x − 2y = 0 − 2×2 = − 4 ≠ 4 L.H.S ≠ R.H.S Therefore, (0, 2) is not a solution of this equation. (ii) (2, 0) Putting x = 2 and y = 0 in the L.H.S of the given equation, x − 2y = 2 − 2 ×...
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(i) (0, 2)

Putting x = 0 and y = 2 in the L.H.S of the given equation,

− 2y = 0 − 2×2 = − 4 ≠ 4

L.H.S ≠ R.H.S

Therefore, (0, 2) is not a solution of this equation.

 

(ii) (2, 0)

Putting x = 2 and y = 0 in the L.H.S of the given equation,

− 2y = 2 − 2 × 0 = 2 ≠ 4

L.H.S ≠ R.H.S

Therefore, (2, 0) is not a solution of this equation.

 

(iii) (4, 0)

Putting x = 4 and y = 0 in the L.H.S of the given equation,

− 2= 4 − 2(0)

= 4 = R.H.S

Therefore, (4, 0) is a solution of this equation.

 

(iv) 

Putting  and in the L.H.S of the given equation,

L.H.S ≠ R.H.S

Therefore, is not a solution of this equation.

 

(v) (1, 1)

Putting x = 1 and y = 1 in the L.H.S of the given equation,

− 2y = 1 − 2(1) = 1 − 2 = − 1 ≠ 4

L.H.S ≠ R.H.S

Therefore, (1, 1) is not a solution of this equation.

 
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