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Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?

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Kinetic energy, Where, Mass of car, m = 1500 kg Velocity of car, v = 60 km/h Hence, 20.8 × 104 J of work is required to stop the car.
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Kinetic energy, 

Where,

Mass of car, m = 1500 kg

Velocity of car, v = 60 km/h 

Hence, 20.8 × 104 J of work is required to stop the car.

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Experienced and certified Tutor for classes till 10th

Mass of car, m = 1500 kgvelocity, v = 60 km/h = Kinetic energy possessed by the car = mv² ⇒ KE = To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ.
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Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60 \times \frac{5}{18}=16.67\ ms^{-1}

Kinetic energy possessed by the car =  \frac{1}{2}  mv² 
⇒ KE =  \frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ

To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ.

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