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Asked by Madhuri Last Modified
Answer 
Tasneem
Mass of the object, m1 = 1 kg
Velocity of the object before collision, v1 = 10 m/s
Mass of the stationary wooden block, m2 = 5 kg
Velocity of the wooden block before collision, v2 = 0 m/s
∴ Total momentum before collision = m1v1 + m2v2
= 1 (10) + 5 (0) = 10 kg m s−1
It is given that after collision, the object and the wooden block stick together.
Total mass of the combined system = m1 + m2
Velocity of the combined object = v
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
m1 v1 + m2v2 = (m1 + m2) v
1 (10) + 5 (0) = (1 + 5) v
The total momentum after collision is also 10 kg m/s.
Total momentum just before the impact = 10 kg m s−1
Total momentum just after the impact = (m1 + m2) v = 
Hence, velocity of the combined object after collision =
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