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Asked by Shamss Last Modified
Answer 
Tasneem
Let the two stones meet after a time t.
(i) For the stone dropped from the tower:
Initial velocity, u = 0
Let the displacement of the stone in time t from the top of the tower be s.
Acceleration due to gravity, g = 9.8 m s−2
From the equation of motion,
(ii) For the stone thrown upwards:
Initial velocity, u = 25 m s−1
Let the displacement of the stone from the ground in time t be s'.
Acceleration due to gravity, g = −9.8 m s−2
Equation of motion,
The combined displacement of both the stones at the meeting point is equal to the height of the tower 100 m.
In 4 s, the falling stone has covered a distance given by equation (1) as
Therefore, the stones will meet after 4 s at a height (100 − 80) = 20 m from the ground
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