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Prove that a cyclic parallelogram is a rectangle.

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Let ABCD be a cyclic parallelogram. ∠A + ∠C = 180° (Opposite angles of a cyclic quadrilateral) ... (1) We know that opposite angles of a parallelogram are equal. ∴ ∠A = ∠C and ∠B = ∠D From equation (1), ∠A + ∠C = 180° ⇒ ∠A + ∠A = 180° ⇒...
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Let ABCD be a cyclic parallelogram.

∠A + ∠C = 180° (Opposite angles of a cyclic quadrilateral) ... (1)

We know that opposite angles of a parallelogram are equal.

∴ ∠A = ∠C and ∠B = ∠D

From equation (1),

∠A + ∠C = 180°

⇒ ∠A + ∠A = 180°

⇒ 2 ∠A = 180°

⇒ ∠A = 90°

Parallelogram ABCD has one of its interior angles as 90°. Therefore, it is a rectangle.

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