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Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Asked by Milan Last Modified
Answer 
Shivam Sharma
(a) 2 m/s, 2 m/s (b) 1.90 m/s, 0.95 m/s
(a) From end A to end B
Distance covered by Joseph while jogging from A to B = 300 m
Time taken to cover that distance = 2 min 30 seconds = 150 s
Total distance covered = 300 m
Total time taken = 150 s
Average speed = 300150 = 2 m/sAverage speed = 300150 = 2 m/s
Displacement = shortest distance between A and B = 300 m
Time interval = 150 s
Average velocity = 300150 = 2 m/sAverage velocity = 300150 = 2 m/s
The average speed and average velocity of Joseph from A to B are the same and equal to 2 m/s.
(b) From end A to end C
Total distance covered = Distance from A to B + Distance from B to C
= 300 + 100 = 400 m
Total time taken = Time taken to travel from A to B + Time taken to travel from B to C = 150 + 60 = 210 s
Average speed = 400210 = 1.90 m/sAverage speed = 400210 = 1.90 m/s
Displacement from A to C = AC = AB − BC = 300 − 100 = 200 m
Time interval = time taken to travel from A to B + time taken to travel from B to C
= 150 + 60 = 210 s
Average velocity = 200210 = 0.95 m/sAverage velocity = 200210 = 0.95 m/s
The average speed of Joseph from A to C is 1.90 m/s and his average velocity is 0.95 m/s.
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