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A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs. 12 per , what will be the cost of painting all these cones? (Use π = 3.14 and take 1.04 = 1.02)
Asked by Sahiba Last Modified
Answer Diameter is 40 Cm first will get the radius in metre
40/100 =0.4
0.4/2= 0.2 (since the radius is always half of the diameter) therefore radius is 0.2m
H=1mTherefore use formula for surface area
πrl= 3.14x0.2x1.02 =0.640 meter square this is for one cone
For 50 cones =
50x 0.640 =32.0 metre square
Cost of painting for meter square area is 12 rs, so the cost for the 32.02-metre square area will be following
12 x 32.02 = 384.34 Rs
Hence it will cost 384.34 rs for 50 cones painting
Tasneem
Radius (r) of cone =
= 0.2 m
Height (h) of cone = 1 m
Slant height (l) of cone =
CSA of each cone = πrl
= (3.14 × 0.2 × 1.02) m2 = 0.64056 m2
CSA of 50 such cones = (50 × 0.64056) m2
= 32.028 m2
Cost of painting 1 m2 area = Rs 12
Cost of painting 32.028 m2 area = Rs (32.028 × 12)
= Rs 384.336
= Rs 384.34 (approximately)
Therefore, it will cost Rs 384.34 in painting 50 such hollow cones.
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