0A monkey climbing a greased pole ascends 12 m and slips down 5 m alternte minutes. If the pole is 63 m high, how lomg will it take for the monkey to reach the top
Ans)
In 2 min, the monkey would have climbed 12 - 5 = 7 m. The pole can be divided into 63 / 7 = 9 parts. The monkey will slip down 9 - 1 =8 times only because it would have reached the top before slipping for the 9th time.
So in (8 * 2 = 16 min), the monkey would have climbed 56 m. Remaining height to be climbed is 63 - 56 = 7 m
Monkey climbs 12 m in 1 min. So to climb the remaining 7 m, it requires 7/12 min = 35 sec.
So total time taken by monkey to reach the top is 16 min 35 sec
