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Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.
Asked by Vikas Last Modified
Answer 
Shivam Sharma
A rough sketch of ΔPQR is as follows.
The steps of construction are as follows.
(i) Draw a line segment QR of length 8 cm.
(ii) At point Q, draw a ray QX making 90º with QR.
(iii) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.
(iv) Join P to R. ΔPQR is the required right-angled triangle.
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