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(i) α-decay of (ii) α-decay of
(iii) β−-decay of (iv) β−-decay of
(v) β+-decay of (vi) β+-decay of
(vii) Electron capture of
Asked by Narayanan Last Modified
Shivam Sharma
α is a nucleus of helium and β is an electron (e− for β− and e+ for β+). In every α-decay, there is a loss of 2 protons and 4 neutrons. In every β+-decay, there is a loss of 1 proton and a neutrino is emitted from the nucleus. In every β−-decay, there is a gain of 1 proton and an antineutrino is emitted from the nucleus.
For the given cases, the various nuclear reactions can be written as:
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