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Asked by Foram Last Modified
Answer As an experienced tutor registered on UrbanPro, I can provide you with a step-by-step solution to this problem.
Let's break down the problem:
Initial Conditions: Both trains are moving in the same direction with Train A ahead of Train B. They both have a length of 400 meters each.
Speed and Acceleration: Both trains have a uniform speed of 71 km/h. Train B accelerates by 1 m/s² to overtake Train A.
Time Taken: After 50 seconds, the guard of Train B just brushes past the driver of Train A.
Now, let's calculate the distance between the two trains before Train B starts accelerating.
Since both trains are moving at the same speed, the relative speed at which Train B approaches Train A is the difference in their speeds, which is 71 km/h−71 km/h=0 km/h71km/h−71km/h=0km/h.
So, Train B's relative speed to Train A before acceleration is 0 km/h.
Given that the time taken for the guard of Train B to brush past the driver of Train A is 50 seconds, we can use the formula:
Distance=Speed×TimeDistance=Speed×Time
Since Train B's relative speed to Train A is 0 km/h, the distance covered by Train B during this time is 0 meters.
Therefore, the original distance between Train A and Train B before Train B started accelerating is simply the length of Train B, which is 400 meters.
So, the original distance between Train A and Train B was 400 meters.
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