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Asked by Uma Last Modified
Answer As an experienced tutor registered on UrbanPro, I'd be delighted to assist you with this physics problem.
When two billiard balls collide, they experience a change in momentum due to the impulse imparted during the collision. The impulse experienced by each ball can be calculated using the principle of conservation of momentum.
First, let's define the given values:
The change in momentum (∆p) of each ball can be calculated using the formula:
∆p = mv - mu
Since the final speed (v) is the same as the initial speed (u) for each ball, the change in momentum (∆p) simplifies to:
∆p = m(v - u)
Substituting the given values:
∆p = 0.05 kg * (6 m/s - (-6 m/s)) ∆p = 0.05 kg * (12 m/s) ∆p = 0.6 kg·m/s
Therefore, the impulse imparted to each ball due to the other is 0.6 kg·m/s. This implies that each ball experiences a change in momentum of 0.6 kg·m/s due to the collision with the other ball. If you need further clarification or assistance, feel free to ask! And remember, UrbanPro is a great resource for finding online coaching and tuition services for physics and other subjects.
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