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Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel.

(a) What is the total capacitance of the combination?

(b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.

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(a) Capacitances of the given capacitors are For the parallel combination of the capacitors, equivalent capacitoris given by the algebraic sum, Therefore, total capacitance of the combination is 9 pF. (b) Supply voltage, V = 100 V The voltage through all the three capacitors is same = V = 100 V Charge...
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(a) Capacitances of the given capacitors are

For the parallel combination of the capacitors, equivalent capacitoris given by the algebraic sum,

Therefore, total capacitance of the combination is 9 pF.

(b) Supply voltage, V = 100 V

The voltage through all the three capacitors is same = V = 100 V

Charge on a capacitor of capacitance C and potential difference V is given by the relation,

q = VC … (i)

For C = 2 pF,

For C = 3 pF,

For C = 4 pF,

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Electrical Engineer With 2 Year Of Teaching Experience

If capacitors are in parallel they adds up.Do you know why? In any electrical system if components are in 1.) series then current will be same throughout the elements ,2.) Parallel voltage will be same throughout the elements.Now...
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If capacitors are in parallel they adds up.Do you know why?
                                                                         In any electrical system if components are in 1.) series then current will be same throughout the elements ,2.) Parallel voltage will be same throughout the elements.

Now coming to second part of your question--please keep in mind that in capacitors Q=CV(where Q=charge),Now as described above voltage will be same in all three capacitors i.e same 100v is applied to 2pF,3pF nad 4pF.
Let say for 2pF--> here C=2pF,V=100,Q=? 
                           
                           
                           = 
Do this for rest of the capacitors.
Now why capacitor adds up in parallel 
 
We know that
                 
 so 
    
since Q=CV and {voltage is same}
 

Ceq=2+3+4=9pF
                     

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If the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + ....... Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pFso, Ceq = C₁ + C₂ + C₃Ceq = 2pF + 3pF + 4pF= 9pF (b) since the capacitors are in parallel, so the potential difference across each...
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If the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
 
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
 
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC
If the capacitors are connected in parallel then equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ + .......
Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF
= 9pF
(b) since the capacitors are in parallel, so the potential difference across each of them is same. e.g., V₁ = V₂ = V₃ = V = 100V
So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC

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Mathematician

A. Total capacitance for parallel combination= 2+3+4 = 9pF B. Charge on each capacitor q=cV Q1 = 2*100 =200 Q2=3*100=300 Q3 = 4*100=400
Comments

Mechanical engineer with 2 years of teaching experience

f the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pFso, Ceq = C₁ + C₂ + C₃Ceq = 2pF + 3pF + 4pF= 9pF b) since the capacitors are in parallel, so the potential difference across each of them is the...
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f the capacitors are connected in parallel, then the equivalent capacitance of capacitors is given by Ceq = C₁ + C₂ + C₃ Here , C₁ = 2pF, C₂ = 3pF and C₃ = 4pF
so, Ceq = C₁ + C₂ + C₃
Ceq = 2pF + 3pF + 4pF= 9pF
b) since the capacitors are in parallel, so the potential difference across each of them is the same. e.g., V₁ = V₂ = V₃ = V = 100V So, charge stored on capacitors are
Q₁ = C₁V = 2pF × 100V = 200pC
Q₂ = C₂V = 3pF × 100V = 300pC
Q₃ = C₃V = 4pF × 100 = 400pC

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Expert Computer,Physics, Mathematics, Science tutor. IIT (Mathematics,Computing)

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