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Asked by Sandeep Last Modified
Answer When a bar magnet is quickly moved towards a conducting loop with a capacitor, the magnetic field passing through the loop changes. According to Faraday's law of electromagnetic induction, this change in magnetic flux induces an electromotive force (emf) and consequently an induced current in the loop.
To determine the polarity of the plates A and B of the capacitor, we can consider Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it.
When the bar magnet is moved towards the conducting loop, the magnetic flux through the loop increases. In response to this change, the induced current in the loop will flow in such a way that it creates a magnetic field opposing the change in magnetic flux.
Using the right-hand rule, we can determine the direction of the induced current. If the bar magnet is approaching the loop, the induced current will flow in such a way that it creates a magnetic field that opposes the approaching magnetic field of the bar magnet.
By the right-hand rule, the induced current will create a magnetic field that flows in the opposite direction to the approaching magnetic field of the bar magnet. This means that the induced current will generate a magnetic field that points away from the approaching magnet.
According to the right-hand rule for the direction of the magnetic field around a current-carrying conductor, the induced current will circulate counterclockwise in the conducting loop.
Now, let's consider the capacitor. When a current flows through a capacitor, it charges the plates of the capacitor. The direction of the induced current in the loop will cause positive charge to accumulate on plate A and negative charge to accumulate on plate B of the capacitor.
Therefore, plate A of the capacitor will have a positive polarity, and plate B will have a negative polarity.
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