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How many solutions are there for 

F(x)= 2^(x) - x-2

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the number of solution is x
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what is the value of i exponent i where i = square root negative 1
0.20788 exp(i*x) = cos(x) + i*sin(x) exp(i*Pi/2) = cos(Pi/2) + i*sin(Pi/2) = i square both the sides now. i^i = exp(i*i*Pi/2) = exp(-Pi/2) = 0.20788 Interesting fact is that i raised to the i-th power is actually a real number!
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