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Asked by Veena Last Modified
Answer Vapour pressure of heptane 
Vapour pressure of octane 
= 46.8 kPa
We know that,
Molar mass of heptane (C7H16) = 7 × 12 + 16 × 1
= 100 g mol−1
Number of moles of heptane 
= 0.26 mol
Molar mass of octane (C8H18) = 8 × 12 + 18 × 1
= 114 g mol−1
Number of moles of octane
= 0.31 mol
Mole fraction of heptane,
= 0.456
And, mole fraction of octane, x2 = 1 − 0.456
= 0.544
Now, partial pressure of heptane, 
= 0.456 × 105.2
= 47.97 kPa
Partial pressure of octane, 
= 0.544 × 46.8
= 25.46 kPa
Hence, vapour pressure of solution, ptotal = p1 + p2
= 47.97 + 25.46
= 73.43 kPa
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