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E=Φ+K.E max.
Where: Φ=work function of electrode
Given: Φ=0
∴ E=K.E of electron where: E= incident energy.
λ=h÷p.
Where: h= plank cons.
P= momentum
K.E = (1÷2)mv* *=2
p= mv
∴ p=√2mK.E.
Now put value in de- Broglie wavelength formula we get,
λ = h÷√2mK.E required and.
Where:λ= de Broglie wavelength
K.E= kinetic energy of electron.
read less
E=Φ+K.E max.
Where: Φ=work function of electrodeGiven: Φ=0
∴ E=K.E of electron where: E= incident energy.
λ=h÷p.
Where: h= plank cons.P= momentum
K.E = (1÷2)mv* *=2
p= mv
∴ p=√2mK.E.
Now put value in de- Broglie wavelength formula we get,λ = h÷√2mK.E required and.
Where:λ= de Broglie wavelength
K.E= kinetic energy of electron.
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