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Asked by Mohd Last Modified
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1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1)
2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide linkage.
read lessIn question one
First reaction H2O2 will act as oxidizing agent because HI is undergoing oxidation so h2o2 will act as oxidizing agent
But in second case in this reaction
H2o2 will be showing disproportionation reaction because it is undergoing oxidation as well reduction at a same time
Option a is correct
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