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Asked by Yatheesh Last Modified
Answer Number of turns in the circular coil, N = 30
Radius of the circular coil, r = 12 cm = 0.12 m
Current in the coil, I = 0.35 A
Angle of dip, δ = 45°
(a) The magnetic field due to current I, at a distance r, is given as:
Where,
= Permeability of free space = 4π × 10−7 Tm A−1
= 5.49 × 10−5 T
The compass needle points from West to East. Hence, the horizontal component of earth’s magnetic field is given as:
BH = Bsin δ
= 5.49 × 10−5 sin 45° = 3.88 × 10−5 T = 0.388 G
(b) When the current in the coil is reversed and the coil is rotated about its vertical axis by an angle of 90 º, the needle will reverse its original direction. In this case, the needle will point from East to West.
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