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Answer Let E1 and E2 be the respective events of choosing a diamond card and a card which is not diamond.
Let A denote the lost card.
Out of 52 cards, 13 cards are diamond and 39 cards are not diamond.
When one diamond card is lost, there are 12 diamond cards out of 51 cards.
Two cards can be drawn out of 12 diamond cards in 
ways.
Similarly, 2 diamond cards can be drawn out of 51 cards in 
ways. The probability of getting two cards, when one diamond card is lost, is given by P (A|E1).
When the lost card is not a diamond, there are 13 diamond cards out of 51 cards.
Two cards can be drawn out of 13 diamond cards in 
ways whereas 2 cards can be drawn out of 51 cards in ways.
The probability of getting two cards, when one card is lost which is not diamond, is given by P (A|E2).
The probability that the lost card is diamond is given by P (E1|A).
By using Bayes’ theorem, we obtain
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