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Asked by Nilesh Last Modified
Answer The magnetic field on the axis of the magnet at a distance d1 = 14 cm, can be written as:
Where,
M = Magnetic moment
= Permeability of free space
H = Horizontal component of the magnetic field at d1
If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.
Hence, the magnetic field at a distance d2, on the equatorial line of the magnet can be written as:
Equating equations (1) and (2), we get:
The new null points will be located 11.1 cm on the normal bisector.
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