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Suppose that two cards are drawn at random from a deck of cards. Let X be the number of aces obtained. Then the value of E(X) is
(A) (B) (C) (D)
Let X denote the number of aces obtained. Therefore, X can take any of the values of 0, 1, or 2.
In a deck of 52 cards, 4 cards are aces. Therefore, there are 48 non-ace cards.
∴ P (X = 0) = P (0 ace and 2 non-ace cards) =
P (X = 1) = P (1 ace and 1 non-ace cards) =
P (X = 2) = P (2 ace and 0 non- ace cards) =
Thus, the probability distribution is as follows.
X | 0 | 1 | 2 |
P(X) |
Then, E(X) =
Therefore, the correct answer is D.
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