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Find the maximum and minimum values, if any, of the following functions given by

(i) f(x) = |x + 2| − 1 (ii) g(x) = − |x + 1| + 3

(iii) h(x) = sin(2x) + 5 (iv) f(x) = |sin 4x + 3|

(v) h(x) = + 1, x (−1, 1)

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(i) f(x) = We know that for every x ∈ R. Therefore, f(x) = for every x ∈ R. The minimum value of f is attained when. ∴Minimum value of f = f(−2) = Hence, function f does not have a maximum value. (ii) g(x) = We know that for every x ∈ R. Therefore, g(x) = for every...
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(i) f(x) = 

We know that for every x ∈ R.

Therefore, f(x) =  for every x ∈ R.

The minimum value of f is attained when.

∴Minimum value of f = f(−2) = 

Hence, function f does not have a maximum value.

 

(ii) g(x) =

We know that for every x ∈ R.

Therefore, g(x) =  for every x ∈ R.

The maximum value of g is attained when.

∴Maximum value of g = g(−1) = 

Hence, function g does not have a minimum value.

 

(iii) h(x) = sin2x + 5

We know that − 1 ≤ sin 2x ≤ 1.

⇒ − 1 + 5 ≤ sin 2x + 5 ≤ 1 + 5

⇒ 4 ≤ sin 2x + 5 ≤ 6

Hence, the maximum and minimum values of h are 6 and 4 respectively.

 

(iv) f(x) =

We know that −1 ≤ sin 4x ≤ 1.

⇒ 2 ≤ sin 4+ 3 ≤ 4

⇒ 2 ≤≤ 4

Hence, the maximum and minimum values of are 4 and 2 respectively.

 

(v) h(x) = x + 1, x ∈ (−1, 1)

Here, if a point x0 is closest to −1, then we find   for all x0∈ (−1, 1).

Also, if x1 is closest to 1, then  for all x1∈ (−1, 1).

Hence, function h(x) has neither maximum nor minimum value in (−1, 1).

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Comments

I am expert in electrical engineering . I have b tech and m tech from nit warangal total experi 10 y

F(-x)= -x+2-1 for maximum. X-2-1 X-2 not equal to f x. F(x)=-x+2-1=-x+1= for minimum.
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For all real values of x, the minimum value of  is

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Let ∴By second derivative test, f is the minimum at x = 1 and the minimum value is given by . The correct answer is D.
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