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An edge of a variable cube is increasing at the rate of 3 cm/s. How fast is the volume of the cube increasing when the edge is 10 cm long?

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Volume of cube = V = x3. ∴ (By chain rule) It is given that, ∴ Thus, when x = 10 cm, Hence, the volume of the cube is increasing at the rate of 900 cm3/s when the edge is 10 cm long.
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Volume of cube =

V = x3.

 (By chain rule)

It is given that,

Thus, when x = 10 cm,

Hence, the volume of the cube is increasing at the rate of 900 cm3/s when the edge is 10 cm long.

 

 

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Let x be the length of a side and V be the volume of the cube. Then, V = x3. ∴ (By chain rule) It is given that, ∴ Thus, when x = 10 cm, Hence, the volume of the cube is increasing at the rate of 900 cm3/s when the edge is 10 cm long.
read more

Let x be the length of a side and V be the volume of the cube. Then,

V = x3.

(By chain rule)

It is given that,

Thus, when x = 10 cm,

Hence, the volume of the cube is increasing at the rate of 900 cm3/s when the edge is 10 cm long.

read less
Comments

Mechanical student with knowledge in core subjects and Mathematics. 3 yrs Experience.

Answer is Volume is increasing at a rate of 1197 cm^3/s. Increase in volume per sec =13^3 -10^3 =1197 cm^3/s
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