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Asked by Hamdaan Last Modified
Answer 
Apoorva Purohit
Water pressure at the bottom, p = 1.1 × 108 Pa
Initial volume of the steel ball, V = 0.32 m3
Bulk modulus of steel, B = 1.6 × 1011 Nm–2
The ball falls at the bottom of the Pacific Ocean, which is 11 km beneath the surface.
Let the change in the volume of the ball on reaching the bottom of the trench be ΔV.
Therefore, the change in volume of the ball on reaching the bottom of the trench is 2.2 × 10–4 m3.
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