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FeO (s) + CO (g) 
Fe (s) + CO2 (g); Kp= 0.265 at 1050 K.
What are the equilibrium partial pressures of CO and CO2 at 1050 K if the initial partial pressures are: pCO = 1.4 atm and 
= 0.80 atm?
Asked by Manjunath Last Modified
Answer For the given reaction,
Since
, the reaction will proceed in the backward direction.
Therefore, we can say that the pressure of CO will increase while the pressure of CO2 will decrease.
Now, let the increase in pressure of CO = decrease in pressure of CO2 be p.
Then, we can write,
Therefore, equilibrium partial of 
And, equilibrium partial pressure of 
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