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Asked by Manish Last Modified
Answer 
Shivam Sharma
Mass of the big structure, M = 50,000 kg
Inner radius of the column, r = 30 cm = 0.3 m
Outer radius of the column, R = 60 cm = 0.6 m
Young’s modulus of steel, Y = 2 × 1011 Pa
Total force exerted, F = Mg = 50000 × 9.8 N
Stress = Force exerted on a single column 
= 122500 N
Young’s modulus, Y
Where,
Area, A = π (R2 – r2) = π ((0.6)2 – (0.3)2)
= 7.22 × 10–7
Hence, the compressional strain of each column is 7.22 × 10–7.
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