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Asked by Meenakshi Last Modified
Answer Foci (±5, 0), the transverse axis is of length 8.
Here, the foci are on the x-axis.
Therefore, the equation of the hyperbola is of the form
.
Since the foci are (±5, 0), c = 5.
Since the length of the transverse axis is 8, 2a = 8 ⇒ a = 4.
We know that a2 + b2 = c2.
∴42 + b2 = 52
⇒ b2 = 25 – 16 = 9
Thus, the equation of the hyperbola is
.
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