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Consider the following species:

N3–, O2–, F, Na+, Mg2+ and Al3+

(a) What is common in them?

(b) Arrange them in the order of increasing ionic radii.

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(a) Each of the given species (ions) has the same number of electrons (10 electrons). Hence, the given species are isoelectronic. (b) The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge. The arrangement of the given species in order of their increasing...
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(a) Each of the given species (ions) has the same number of electrons (10 electrons). Hence, the given species are isoelectronic.

(b) The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge.

The arrangement of the given species in order of their increasing nuclear charge is as follows:

N3– < O2– < F < Na+ < Mg2+ < Al3+

Nuclear charge = +7 +8 +9 +11 +12 +13

Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:

Al3+ < Mg2+ < Na+ < F < O2– < N3–

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Chemistry- neet and mains and iit foundation teacher from last 3 years in krishnaswany narayana

a)The above cations and anions havings common character in their outer most shell having 10 electrons, So all the ions obey the octate rule and get their stability. b)The ionic radii increases with decrease of magnatidues of nuclear charge. Al3+<mg2+<Na1+<F1-<O2-<N3-
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