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What subjects are needed to join the navy in 11th and 12th?

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Maths, physics and chemistry are mandatory
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Maths,physics, chemistry
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Related Questions

For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?
The value of k should be equal to 2, and thus the equations, 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines
Aparna
Why is there linear algebra but not nonlinear algebra?
Non-linear algebra is there, it is just called algebra. The most famous examples these days are machine learning algorithms.associating linearity simplifies the analysis by far. So we study this line of algebra separately.
Kadar
0 0
7
Simplify: log base 6 (216) + [log (42) - log (6)] / log (49)?
216 = 6^3; log 42 - log 6 = log (42/6) = log 7 ; / log (49) = log 7 / 2 log 7 = 1/2 ; Answer = 3 + 1/2 = 3.5
Vishal
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5
What I should do study for coming in merit list of 10th board exam?
Determination and regularity are key points. Make plan, make small achievable goal and do it for that. Make schedule of daily and must follow with giving them high preference.
Hole

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Related Lessons

Trigonometry
1) Sinθ=perpendicular/hypotenuse 2) Cosθ=base/hypotenuse 3) Tanθ=perpendicular/base = Sinθ/Cosθ 4) Cotθ=base/perpendicular = Cosθ/Sinθ = 1/Tanθ 5)...
P

Prasannakumar Kalahasthi

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AREA OF THE SEMI CIRCLE
The area of a semi circle is the total space inside the semi circle. If radius of the circle = r Then, Area of the circle = (1/2)xπr2 sqare units Here, π=22/7=3.14 aproximately Ex:- radius...

Graph of Ellipses and Circle Step by Step: 9x^2 + y^2 + 126x + 2y + 433
Graph of Ellipses and Circle Step by Step: 9x^2 + y^2 + 126x + 2y + 433

Equation of the median of a triangle with coordinates A ( 5 -4 ) , B (2 , 5 ) and C (4 ,-1 ) passing through vertex A.
Median from vertex A bisects the opposite side B C. Let D be the mid point of BC. Coordinates of D ( 3 , 2) Using two point formula of straight line, we can find the equation of the median. A (5 ,-4...

Find DE^2 (Important For RMO)
Question: Solution: AD + AE = 25AD = xAE = 25-x1/2(Area of triangle ABC) = Area of triangle ADE1/2 ( 1/2× 16×18×SinA) = 1/2 *(25-x)x * SinA=> x = 9 = AD25-x = 16 = AE 9²+16²-DE²/(2×9×16)...

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