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Asked by Abdul Last Modified
Answer 
Let P(x)=ax3+3x2-bx-6
since -1,-2 are zeroes of the given polynomial, we have P(-1)=0,P(-2)=0
So, -a+b-3=0 and -4a+b+3=0
By solving, we get a=2, b=5
So given polynomial is 2x3+3x2-5x-6
Compare given polynomial with ax3+bx2+cx+d
We get a=2, b=3, c=-5, d=-6 and zeroes are p=-1,q=-2,r
We have P+q+r=-3/2, p×q×r=6/2=3
So, -3+r=-3/2⇒r=3/2
Another zeroes of the polynomial is 3/2
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