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(ii)

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Learn Exercise 8.1

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Let us consider a right triangle ABC, right-angled at point B. If BC is 7k, then AB will be 8k, where k is a positive integer. Applying Pythagoras theorem in ΔABC, we obtain AC2 = AB2 + BC2 = (8k)2 + (7k)2 = 64k2 + 49k2 = 113k2 AC = (i) (ii) cot2 θ = (cot θ)2 = =
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Let us consider a right triangle ABC, right-angled at point B.

If BC is 7k, then AB will be 8k, where k is a positive integer.

Applying Pythagoras theorem in ΔABC, we obtain

AC2 = AB2 + BC2

= (8k)2 + (7k)2

= 64k2 + 49k2

= 113k2

AC = 

(i) 

(ii) cot2 θ = (cot θ)2 = 

 

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Setting the foundation right through fundamentals.

i) Theorems used:
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i)

Theorems used:

 

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