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(ii)
Asked by Latha Last Modified
Answer 
Tasneem
Let us consider a right triangle ABC, right-angled at point B.
If BC is 7k, then AB will be 8k, where k is a positive integer.
Applying Pythagoras theorem in ΔABC, we obtain
AC2 = AB2 + BC2
= (8k)2 + (7k)2
= 64k2 + 49k2
= 113k2
AC = 
(i)
(ii) cot2 θ = (cot θ)2 = 
= 
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Deleted User
Setting the foundation right through fundamentals.
i)
Theorems used:
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